$8\cdot5+8$
$-12\:-\:\left(-17\right)$
$4x+12=4$
$x+x^{-1}=6$
$\log_x\left(\frac{2x-5}{x-4}\right)=-1$
$2x+1<3x-1$
$\left(-\frac{x}{2}+\frac{y}{6}\right)^2$
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