$\frac{5x^3-2x+1}{x+1}$
$10\cdot9\cdot8$
$8\:-5w\:=-37$
$49^2-36y^2$
$9d-2,\:5d+28$
$\sin^2x-0.75=0$
$\frac{\cos\:\left(\theta\:\right)-\sec\:\left(\theta\:\right)}{\sin\:\left(\theta\:\right)}$
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