$\int\frac{x-9}{\left(2x-3\right)\left(x+3\right)^2}dx$
$\frac{1}{\sqrt{x+7}}$
$\left(-36\right)\left(-8\right):-16$
$27+a^3b^9$
$\left(f+15\right)^2$
$\frac{2x^2}{5}-xy+\frac{y^2}{4}$
$\int\left(6x^7\left(x^8-4\right)^3\right)dx$
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