$\frac{4x^5+2x^3-3x\:+1}{x^2-2}$
$\frac{-\cot\left(a\right)-\tan\left(a\right)}{\cot\left(a\right)}=-\sec^2\left(a\right)$
$12.38\cdot2.50$
$\left(9b^3+d\right)^3$
$\frac{2x^3-6x^2+x-1^{-1}}{2x^2+1}$
$8\frac{1}{4}+3\left(3\right)$
$-1\:\cdot6$
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