$n+3+-10$
$\left(5x-.03\right)\left(5x+.03\right)$
$\frac{3x}{3x-6}-\frac{2}{2x+4}=\frac{12}{x^2-4}$
$\left(x^c+3y^u\right)\left(x^c+7y^n\right)$
$\left(a-b-1\right)\left(a-b+1\right)$
$\left(-6x+y\right)+\left(-3x+5y\right)$
$\sec\left(x\right)-\tan\left(x\right)=\sec\left(x\right)-\cos\left(x\right)$
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