$\frac{12x^3-13^2-8x+3}{4x+1}$
$-1\left(r+48\right)+664<433$
$\frac{1}{x-3}+2=\frac{4x-21}{2x-11}$
$\lim_{x\to\infty}\left(\frac{4}{4x-3}\right)$
$\frac{3x^2}{6x^2+3}$
$\int t^2e^xdx$
$\lim_{x\to\infty}\left(5^{x+2}\right)$
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