$= \frac { a ^ { m + 8 } } { a ^ { m + 3 } }$
$\left(x-2\right)>2$
$\int\frac{7}{\left(25x^2+4\right)}dx$
$\frac{-4x}{3x-2}+1$
$10^{x^2-4}=1$
$\frac{x^4}{4x^3}$
$\lim_{x\to0}\left(\frac{36x\cos\left(x\right)-36\sin\left(x\right)}{x\sin^2\left(x\right)}\right)$
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