$\lim_{x\to\infty}\left(1+\frac{1}{2x}\right)^{x^2}$

$\int\tan\left(2x\right)\sec^2\left(2x\right)dx$

$\lim_{x\to2}\left(\frac{x^2-x-2}{x^2-5x+6}\right)$

$-2\:+\:9\:+\:5\:+\:6\:+\:3\:+\:3$

$y\left(1-x\right)\frac{dy}{dx}=x\left(2y-1\right)$

$1+\frac{\tan^2x}{1+\sec^2x}$

$\cos\left(x+4y\right)$