$\sec\left(x\right)\left(\tan^2\left(x\right)-\sec^2\left(x\right)\right)$

$\int4x^3e^{-2x}dx$

$9m+12\cdot9m-12$

$-\left(+17\right)+\left(-18\right)+\left(+11\right)-\left(-18\right)$

$\frac{dy}{dx}=\frac{y}{x}\:+\:\frac{x^2}{y^2}+1$

$4p\:+\:6q\:=\:20$

$x^3+x^2-3x+2;x=1$