$3\ln\left(x\right)+\frac{1}{2}\ln\left(x+6\right)-2\ln\left(x+6\right)$
$\frac{-3}{\sqrt{1-9x^2}}$
$7x-38=3x-10$
$6\left(4x-y\right)$
$\left(xy+y^2\right)dy+\left(xy+x^2\right)dx=0$
$\left(\frac{2x^2}{4x^4}\right)^3$
$|4|\:\cdot\:-3\:=\:1$
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