$3x^2-4x^2-19\cdot3x^2-4x+60$
$3y+2xy-5y+3x-2-xy+x$
$\frac{dx}{dy}=4y^3\left(1+x^2\right)$
$\left(+5\right)\left(-4\right)\left(-8\right)$
$\sqrt{398.94}$
$\sin\left(x+3\right)=\sin\left(x\right)$
$\frac{dy}{dx}\left(4\sin\left(x-3y\right)\right)$
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