$-4-\:\left(23-21\right)-\left(18\right)$
$\left(8x+4\right)\left(x-9\right)$
$x^3-b^9$
$\left(5+4\right)\cdot12$
$-2\left(-13+8\right)^2$
$\int\frac{3x+4}{\left(x-6\right)^2\left(x-3\right)}dx$
$a^4b^4=16$
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