$\lim_{x\to0}\left(\frac{x^2}{\left(\frac{\left(6\cdot\ln\left(3x+1\right)\right)}{3x+1}\right)}\right)$
$\sec2x\cos2x\sec2x-\csc2x$
$\frac{2xy}{yx}$
$2-4z+8z$
$2x+34=2x-34$
$25m^{n-1}-32m^{n-1}$
$375+-3$
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