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Factor the trinomial $6x^2-19x+15$ of the form $ax^2+bx+c$, first, make the product of $6$ and $15$
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$\left(6\right)\left(15\right)=90$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 6x^2-19x+15=0. Factor the trinomial 6x^2-19x+15 of the form ax^2+bx+c, first, make the product of 6 and 15. Now, find two numbers that multiplied give us 90 and add up to -19. Rewrite the original expression. Factor 6x^2-10x-9x+15 by the greatest common divisor 3.