$x^2-9<10$
$\frac{x^{5}-x}{x+1}$
$98+x=0$
$\frac{dy}{dx}=\frac{16x^3}{y^4}$
$\frac{d^2}{dx^2}\left(e^{x^2-4x+5}\right)$
$\sqrt{5}+3\sqrt{5}$
$0.75\:\:\frac{3}{5}$
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