$\lim\:_{x\to\:\:\infty}\left(\left(3x\right)^{\frac{6}{x}}\right)$

$\sqrt{3}\sqrt{7n}$

$2\cdot\left(-3-5\right)-\left|2-3\cdot\left(4-1\right)-\left(-3\right)\right|+1$

$f\left(x\right)=7x^4\left(x^2-9x\right)$

$\int\left(\frac{y}{\sqrt{4+y^2}}\right)dy$

$-7x^2\:para\:x=-1$

$x^2+10x+9=x-1$