$\left(-2x^2+3y^2-1\right)\left(6x^3-2y^3\right);\:x=-2;\:y=-3$
$\left(2a^4+3b^2\right)^2$
$2x^2-7x-28$
$3\left(x+4\right)=-5x-36$
$\left(5x^2-\frac{5}{4}\right)^4$
$\frac{dy}{dx}=\frac{200e^{-\frac{x}{100}}+y}{100}$
$x\left(x+3\right)=5x+4$
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