$f\left(x\right)=\frac{3e^{x}}{x^{2}+x}$
$\frac{2x^2-3}{x+4}$
$\frac{dy}{dx}=\frac{y\cos\left(2x\right)}{1+3y^2}$
$\frac{\left(3x+21\right)\left(3x-2\right)}{3}$
$36x^2-4=0$
$5^5^5^5^5$
$\frac{6x+4}{2}$
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