$\left(x^3-y^3\right)^2$
$\frac{x^2+3x+2}{x+3}$
$y'\:+3y=15$
$\frac{dy}{dx}=\left(y+1\right)\left(y-4\right)$
$\frac{dy}{dx}=2+2y+x+yx$
$\left(6m^4-7n^2\right)^2$
$x+12\le-10$
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