$-m+5=-\left(m-5\right)$
$\int_0^5-e^{-x}dx$
$\frac{\left(4^5\cdot8^4\right)}{\left(4^3\cdot8\right)}$
$\frac{-3x-8}{-4}$
$5\left(4j\right)$
$\left(\frac{8}{3}x^2+\frac{4}{7}n^5\right)^2$
$y'+y=e^{3x}$
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