$\int\frac{x}{2x^2-6}dx$
$1+\int_1^{\infty}\left(\frac{1}{x^2}\right)dx$
$-2x-3>x-4$
$\left(3f^5+2f^3\right)\left(-3f^5+2f^3\right)$
$-64\frac{1}{1}\cdot\sqrt{100}$
$\left(2a+3b-18a+5b\right)^3$
$\frac{2}{5}x-3\ge2x+8$
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