$\lim_{x\to0}\left(x^2ln\left(x\right)+1\right)$

$-5x\left(8x^2+1\right)$

$\left(6^5\right)^6$

$\tan\left(x\right)\cdot\left(\cos\left(x\right)-\csc\left(x\right)\right)$

$\lim_{x\to\infty}\left(\frac{7\sqrt{4n+21}}{\sqrt{n}}\right)\left(\frac{n+1}{2}\right)$

$2x^2-3\le3x^2-4x$

$\frac{2x^4-3x^3+x}{3x^2+6x}$