$\sqrt{300}-\sqrt{75}$
$8\cdot10$
$\log_{10}\left(n\right)\:=\:1000$
$-2^2\cdot\left(-1\right)^3\cdot\left(-5\right)^0$
$\frac{3y-6}{2}>\frac{2y+5}{6}$
$\left(1\right)^{15}$
$\frac{d}{dx}\left(\frac{x\sqrt{x^2+3}}{\left(x+8\right)^{\frac{1}{3}}}\right)$
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