$8b^3+5a^2+-7a^2+-3b^3+3c-b^2$
$\frac{dy}{dx}=\frac{y}{x\left(y-3\right)}$
$tan2\:sin2=tan2\:-\:sin2$
$y^2+12y+36-x^2-14x-49$
$\left(-2\right)^2+2\left(-2\right)-1$
$\frac{kd^2}{2}=mg\cdot\left(h+d\right)$
$\sqrt[2]{-36}$
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