$\left(m^2-5\right)\left(m^2+5\right)$
$-3\sin\left(x\right)+3\cos\left(x\right)\cdot\tan\left(x\right)=0$
$\int_{-1}^13\left(1-x^2\right)dx$
$11-7-9+3+7$
$x^2+2x-1+x^2-2x+7$
$\frac{x-2}{7}+\frac{x-4}{21}=-2$
$\frac{dy}{dx}=\frac{y}{x}\:+\:x$
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