$\frac{12m^3+5m^2+13m+14}{3m+2}$
$\frac{\left(2x^3-7x+8\right)}{\:\left(3x^2-4\right)}$
$x^2-1>\frac{3}{4}$
$x+12\le-10$
$\left(4v+7z\right)^2$
$5\cdot\left(4\cdot\left(-2\right)\right)+3\cdot\left(-2\right)$
$5x^2-9x+18$
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