$2-3x\ge0$
$\int_0^3\frac{t^4+5}{4+t^2}dx$
$1^3+1^2-1$
$-5x-5<8$
$\int\frac{x-29}{x^2-3x+4}dx$
$3\left(x\:-\:2\right)\:-\:4\left(3\:-\:5x\right)\:-\:16x\:+\:7\:$
$5.5x^2-6x^2-3y+\frac{6y^2}{y}-105x^2$
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