$x^2+y^2-25=0$
$\lim_{x\to\infty}\left(\left(2x\right)\sin\left(\frac{1}{x}\right)\right)$
$-32x+40$
$-4\left(1\right)\left(9\right)$
$\log_{25}\left(x\right)=\frac{3}{2}$
$\frac{1}{2}\int\sin^2\left(x\right)dx$
$x^2+26x+52$
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