$\left(12x^3y^5z^4\right):\left(3x^2y^2z^3\right)$
$\frac{\left(2x-1\right)\left(4x^2+2x+1\right)}{16x^3-2}$
$\frac{dy}{dx}=y=tan\:\left(2x-3\right)$
$\int\frac{1}{x^2\sqrt{9+4x^2}}dx$
$121-81b^2$
$\left|2\right|\cdot\left|3\right|$
$\:\:25x^2\:-9$
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