$sin^{2\:}x\:+\:cos^2\:x\:=\:sec^2\:x\:-\:tan^2\:x$
$\int\frac{x^2+2x-12}{x\left(x^2+4\right)}dx$
$\frac{15.070}{27.400}$
$5tanb=10$
$\lim_{x\to0}\left(\left(x+e^{\left(3x\right)}\right)^{\left(\frac{1}{x}\right)}\right)$
$x^4+0+9x^2+4x+12$
$16a^2-40ab+25b^2$
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