$\lim_{x\to0}\left(\frac{six}{ln\left(2e^x-1\right)}\right)$
$3x^3-2x-1$
$-56+2$
$\left(\frac{x^2}{y}\:-\:\frac{y}{x}\right)^2$
$\lim_{x\to\infty}\left(\frac{3x}{7-x^2}\right)$
$5-[\left(-10\right)+5-2]$
$x^4-3x^2+x,\:para\:x=-3$
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