$\frac{7}{3-x}=0$

$\left(9\frac{3}{4}\right)\left(\frac{16}{3}\right)\left(-7\right)$

$\lim_{x\to1}\left(\sqrt{x^2+1}\right)$

$\frac{\left(-6+108x\right)}{12}$

$\left(x-3\right)^2>\left(x+4\right)^2$

$\sqrt[3]{625x^5y^2}$

$\int\frac{6}{\left(x+1\right)\left(x^2-4\right)}dx$