$4=\frac{-8+x}{2}$
$\frac{2x^3-4x^2-2x+3}{-3}$
$n^2-3n-60$
$-\frac{1}{3}\:.\:3$
$25\:-\:x\:4\:=\:25\:-\:4x$
$2x<6$
$\left(x-2\right)\left(x^4-9x+8\right)$
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