$2\cot^2\left(x\right)=-1+3\cot^2\left(x\right)$
$1+e^{3x}y^'=0$
$27a^3-8b^3$
$7x-3\ge10$
$2.5752=\frac{1.8}{\log_{10}\left(a\right)}$
$e^2+ydx+\left(2+x+ye^y\right)dy=0$
$\int\frac{x^2}{\left(1+x^3\right)^{1.8}}dx$
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