$\int\left(6-x^3\right)x^2dx$
$\frac{8w^3h^4}{4wh^2}$
$x^3+2x^2+x-4$
$\left(x^2+12\right)\left(x^2-8\right)$
$\frac{a^33^3+b^3-ab\:}{a^2-b^2}$
$\left(2x+3\right).\left(2x-5\right)-\left(x-3\right)^2$
$y'=4x-4$
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