$\int\left(\frac{x^2+x-8}{x^3-4x}\right)dx$
$\frac{1-\sec^2\left(x\right)}{1-\csc^2\left(x\right)}$
$9y+6+36$
$x\left(x-1\right)+\left(x-1\right)$
$\left(2yx+3x\right)dx=-xdy$
$\sqrt[4]{x^4}+6$
$0,3+0,5$
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