$3x-6y$
$\int40x^4\csc^2\left(9x^5+10\right)dx$
$\left(\frac{3b^2}{a^{-2}}+\frac{a^{-3}}{b^2}\right)^2$
$\:\:\left(3x-2\right)^2+\left(3x-2\right)\left(3x+2\right)$
$\ln\left(a^2-27\right)=\ln\left(7a+3\right)$
$-1+9+\left(-1\right)+7+\left(-3\right)$
$20+\:57$
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