$\sqrt{7-2x}-x=4$
$taylor\:\frac{1}{x}$
$\int\frac{\left(5x+7\right)}{\left(x^2+4x+4\right)}dx$
$\left(6x+2\right)\left(3x^2+2x\right)^3$
$tanx=\frac{sinx}{cosx}$
$-3\:x\:-2\:x\:-1$
$3e+7-e\:2e+10+2e-3$
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