$\left(4-m\right)^2$
$cos\:x\:=\:0.77$
$\left(m-2\right)\left(m.3\right)$
$a^2-5a$
$\frac{25a^3b\:+15ab^3}{5ab}$
$\left(6-3a\right)\left(-10a+5\right)$
$\frac{d}{dx}\left(4y-8x^3=20\right)$
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