$\frac{dy}{dx}=\frac{y}{2x}+\frac{x}{2y}$
$2^{x^2+x}=\frac{1}{4}$
$x^3+y+3x^2y=y$
$6r-10\ge\:5r-19$
$2\cdot\left[8-4\cdot\left(10-6\right)-\left(-3-2\right)\right]$
$y'=-y$
$x^2-\frac{1}{3x}x+\frac{1}{36}$
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