$\frac{d}{dx}\left(1-x\right)tanh^{-1}x$
$\lim_{x\to0}\left(17x-cosx\right)^{\frac{1}{x}}$
$\int\left(\tan\:x-1\right)^2dx$
$9x^4-4x^2$
$y'+12xy^8=0$
$1575\cdot60$
$y^2=6-y^2$
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