$\left(-\frac{5}{4}y-\frac{5}{6}\right)^2$
$\frac{d}{dx}\left(y=cot^{-1}\sqrt{6x}\right)$
$\sqrt{x^2}-7$
$-7+7+2-12-3+8$
$7x-\left(x-1\right)+\left(2x+3\right)$
$8y+4x+8y+4x$
$y'\:=\:xy\:+\:2x$
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