$\frac{\sqrt[3]{64a^2b^2}}{\sqrt[3]{27\left(a^4b\right)^{-1}}}\cdot\sqrt[3]{a^6b^9}$
$\frac{x^2+3x+x^3+10}{x^2+2x+1}$
$3\cdot0.04$
$-x-12>-8$
$-3\cdot\left(-2+-1\right)$
$\frac{d}{dx}\left(2x\:+\:3y\:-\:xy\:=\:3\right)$
$\frac{4^3}{4^{-1}}$
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