$-12^3$
$x^2+4x-168=0$
$5\cdot5\cdot\left(-10\right)$
$9\left(n+6\right)$
$x^2+6+3$
$\int\frac{x+3}{\left(x-4\right)^2}dx$
$\left(10-c^2\right)^3$
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