$\frac{12}{4}+2\frac{1}{2}$

$\frac{\left(2x-6\right)\left(2x+6\right)}{2}$

$\int\frac{x}{\sqrt{8-x^2-4x}}dx$

$\lim_{x\to\infty}\left(\frac{\sqrt{x^2+8}}{ln\left(x\right)}\right)$

$2x\left(4x-3y\left(2y-3x\right)-2x\left(3x+2y\right)-4x^2\right)-3y^2$

$\frac{x-3}{x^4-1}$

$x^2\frac{dy}{dx}=1+x$