$f\left(x\right)=x^2+2x+1$
$\frac{tan\:x\:+\:cot\:y}{tan\left(x\right)cot\left(y\right)}\:=\:tan\:y\:$
$8+1$
$-x\:+\:-8\:=\:16$
$\int in\:\sqrt{x}\:dx$
$\frac{x^{2}}{1-x^{6}}$
$\int_0^1\frac{\left(6x^2+1\right)}{\left(6x^2+3x+3\right)}dx$
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