$9x^2-24x-16$
$2\sqrt{\frac{1}{4}}-\sqrt{\frac{3}{\frac{1}{3}}}+\sqrt{\frac{24}{5}\:\left(\frac{1}{3}\right)\left(10\right)}$
$\lim_{x\to-1}\left(2x^3-4x-4\right)$
$\frac{2-x}{x^2-4}$
$6\cos^2\left(x\right)+\cos\left(x\right)=1$
$6x^2-3y^2=1$
$a^6.\:a^8$
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