$f\left(x\right)=log\:x^6$
$\frac{dy}{dx}=\frac{4}{x^2+4}$
$\frac{dy}{dx}\left(y^2-4xy+8y+3\right)$
$6+3\left(5x+2\right)-10x$
$\frac{dy}{dx}=\frac{x-3}{y-4}$
$9y+8y-z+2z$
$10\infty6$
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