$\frac{25^2}{4}+\frac{20xy}{3}+1\frac{6y^2}{9}$
$cotg\left(x-\pi\right)=\:-1$
$\left(7b^2+3x^3\right)\left(7b^2\right)$
$2\cot\sin^2$
$\left(5x-1\right)\left(2x+3\right)$
$14\left(3+1\right)-12\left(-1-2\right)-42\left(9-9\right)$
$\sqrt[3]{b^6}$
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