$\frac{1}{6}x-\frac{1}{3}\ge\:\frac{3}{4}-\frac{3}{2}x$
$+\:263\:-\:\left(-259\right)\:-\:\left(-13\right)\:-\:1$
$\left(-4x^2\:+\:9x\right)^2$
$\frac{dx}{dy}=e^{x+y}$
$\left(38-4x^2\right)$
$m^3+6m^2+12m+8$
$-4x-7y+3y-x+2x^2+x+3x^2$
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